A man goes 35 m due north and then 12 km due East. How far is he from the starting point?
Answers
Displacement=final position-initital position
Let's the starting point be O
From O he is going at point A in south whose distance from O is 12 m
From A he is going at point B in west whose distance from A is 35m
If we join all three points together we got a right angle triangle OAB.
WHOSE OA=12m=a
AB=35M=b
according to pithagoras theoram
BO=UNDERROOT(a^2+b^2)
=underroot(12^2+35^2)
=underroot(144+1225)
=underroot(1369)
=underroot(37×37)
=+-37
since displacement cant be negative so the answer will be 37m
Answer:
√(12²+35²)
Step-by-step explanation:
12
----- ↑→→→→→
! ↑ /
35 ! ↑ /√(12²+35²)
! .↑.. /
---- mans starting point