Question

.A man goes 36km due north and then 40km due east. How far away is he from his initial positlon?
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Answer 1

Answer:

ok here is the answer

Step-by-step explanation:

(36+40) km=76 km

Answer 2

Answer:

See the attachment ⤴️

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²c² = 900 + 1600

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²c² = 900 + 1600c² = 2500

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²c² = 900 + 1600c² = 2500c = √2500

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²c² = 900 + 1600c² = 2500c = √2500c = 50 km

We will use Pythagorean Theorem. to find the diagonal distance from the initial position to the final point. The diagonal will be the hypotenuse in the equation:a² + b² = c²c² = 30² + 40²c² = 900 + 1600c² = 2500c = √2500c = 50 kmAnswer He is 50 km away from his initial position.

Step-by-step explanation:

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