Math, asked by meena2012singh, 4 months ago

A man goes 5 km due north and then 12 km due east. How far is he away from his
initial position?

Answers

Answered by pothurajuyaswanth
0

Answer:

12 + 5 = 17 km

Step-by-step explanation:

A man goes 5 km due to North and then 12 km due to east . how far is he away from his initial position .

Answered by Chattyyrr
1

5 km towards north

12 km to east

Let distance away from initial position be x.

Drawing a figure, a right angle triangle will be formed, therefore, by Pythagoras Theorem,

x²=12²+5²

x=√169

x=13km

Therefore, the man is 13 km away from his initial position.

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