Question

a man goes 6 centimetre to East then 8cm to North direction then his distance from the starting point is______m​

Answer 1

Step-by-step explanation:

14cm in meter you change by your own

Answer 2

Step-by-step explanation:

$AC = \sqrt{ {6}^{2} + {8}^{2} } \\ = \sqrt{36 + 64} \\ = \sqrt{100} \\ = 10 \: cm$

Hence man will 10 cm away from initial point....