Question

a man goes 6 metres due east then 8 do not his distance from starting point is​

Answer 1

Answer:

Let the initial position of the man is at ‘O’.let 'A.’be the way he stops on the east direction. Let 'B’baby doll with his tops on the north direction.

The shortest distance from O to B is OB.

OA=8m, AB=6m

From the Pythagoras theorem, in a triangle OAB,(diagonal)^2=(side)^2+(side)^2

(OB)^2=(OA)^2+(AB)^2

=6^2+8^2=(OB)^2

√36+64=OB

√100=OB

OB=10 m

Step-by-step explanation:

Answer 2

Answer:

Hey mate, Good evening ♡

#Here's ur answer ☆☆☆

Step-by-step explanation:

$by \: pythagoreos \: theoram \\ \: h = \sqrt{6 {}^{2} + 8 {}^{2} } = 10m$

$direction - \\ towards \: south \: west$

Hope this helps you....

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