Question

A man goes 8m due west and then 15m due north.how far is he from starting point

Answer 1

He is 17 meters from the starting point hope it helped

Answer 2

Answer:

He moves in the shape of a right angle triangle

using pythagoras theorem

8^2+15^2=hypotenuse^2

64+225=289

$\sqrt{289}$=17

hence the is 17m far from the starting point

Step-by-step explanation: