a man goes downstream and covers a distance between two ports in 5 hours while it covers the same distance upstream in 6 hours if the speed of the stream is 1 kilometre per hour find the speed of the Schema in stillwater
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let the speed of streamer be x.
then the speed in downstream in one hour is (1+x)km
in 5hrs=5(1+x)
in upstream = (1-x)km
in 6hrs = 6(1-x)
then,
5(1+x)=6(1-x)
5+5x = 6-6x
5-6=-6x-5x
-1= -11x
x=11km
then the speed in downstream in one hour is (1+x)km
in 5hrs=5(1+x)
in upstream = (1-x)km
in 6hrs = 6(1-x)
then,
5(1+x)=6(1-x)
5+5x = 6-6x
5-6=-6x-5x
-1= -11x
x=11km
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