A man goes from A to B at 40 kmph and returns from B to A at 60 kmph. if he takes 5hrs in all, what is the distance between A and B
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Answer:
500 kmphs
Step-by-step explanation:
40+60×5
100×5
500kmphs
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if distance is D Between A and B
ongoing time+incoming time=Time taken=5hrs
D/40+D/60=5
60D+40D/(40)(60)=5
100D/2400=5
D/24=5
D=120
Therefore distance=120km
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