Physics, asked by deepakdk11x, 1 year ago

A man goes from A to B of distance 20 meter in 5 minute, then B to c distance 30 meter in 4 minute and C to D of distance 10 meter in 1 minute and return to A in 12 minutes. Find his average speed in meter per second.

Answers

Answered by Cris01
1
average speed =total distance /total time
av. speed =(20+30+10+60)/(5+4+1+12)
=120/22 m/min =(120*60)/22
=7200/22m/s = 3600/11 m/s

deepakdk11x: 60 kase aaya
Cris01: A se B tak distance 20 + 30 + 10 matlab 60 hai aur vo vapas bhi jata hai to pura 2 baar 60 chalega
deepakdk11x: Matlab
Cris01: vo pura 60*2 = 120 chalega
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