A man goes from A to B of distance 20 meter in 5 minute, then B to c distance 30 meter in 4 minute and C to D of distance 10 meter in 1 minute and return to A in 12 minutes. Find his average speed in meter per second.
Answers
Answered by
1
average speed =total distance /total time
av. speed =(20+30+10+60)/(5+4+1+12)
=120/22 m/min =(120*60)/22
=7200/22m/s = 3600/11 m/s
av. speed =(20+30+10+60)/(5+4+1+12)
=120/22 m/min =(120*60)/22
=7200/22m/s = 3600/11 m/s
deepakdk11x:
60 kase aaya
Similar questions