in a circle of diameter 40 cm the length of the chord is 20 cm find the length minor arc of the called
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Step-by-step explanation:
in question given
diameter = 40 cm
radius = D/2
= 40/2
= 20cm.
the length of a chord is 20cm.
a/q
∆ OAB is equilateral traingle.
θ = 60°
l = 20 × 60° × π / 180°
l = 20π / 3cm
thus,
the length of the minor arc of the chord
20π / 3cm
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