A man goes from city x to city y and return to city x on his motorbike. The distance between the two cities is 260 km and the man taken 4 hours 20 minutes to complete his journey.
Q. Find his average speed and average velocity in kmph.
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Answered by
4
DISTANCE= 260 KM
TIME= 4 HOURS 20 MINUTES= 4 1/3 HOURS
AVERAGE SPEED= TOTAL DISTANCE/TOTAL TIME=
260KM/4 1/3=
260/13/3=
260*3/13=
60KM/Hr
DISPLACEMENT=0(INITIAL AND FINAL POSITION IS SAME)
TIME= 13/3Hr
AVERAGE VELOCITY= DISPLACEMENT/TOTAL TIME=
0/13/3= 0*3/13=0/13=0
THEREFORE AVERAGE SPEED=60KM/Hr
and AVERAGE VELOCITY = 0
TIME= 4 HOURS 20 MINUTES= 4 1/3 HOURS
AVERAGE SPEED= TOTAL DISTANCE/TOTAL TIME=
260KM/4 1/3=
260/13/3=
260*3/13=
60KM/Hr
DISPLACEMENT=0(INITIAL AND FINAL POSITION IS SAME)
TIME= 13/3Hr
AVERAGE VELOCITY= DISPLACEMENT/TOTAL TIME=
0/13/3= 0*3/13=0/13=0
THEREFORE AVERAGE SPEED=60KM/Hr
and AVERAGE VELOCITY = 0
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