Question

A man goes from his home to the grocery
shop at a speed of 6 km/h and returns at
a speed of 9 km/h. If the distance from his home to shop is 900m,calculate the total time (in minutes) and (in hours if you can)that he spends travelling his home to the shop and back.​

Answer 1

Step-by-step explanation:

Step-by-step explanation:

Answer :-

→ Total time [in minutes] = 15 minutes

→ Total time [in hours] = 0.25 hour

Explanation :-

We have :-

• Speed during first journey = 6 km/h

• Speed during return journey = 9 km/h

• Distance = 900 m = 0.9 km

________________________________

For first journey :-

⇒ Time = Distance/Speed

⇒ t₁ = 0.9/6

⇒ t₁ = 0.15 h

For return journey :-

⇒ Time = Distance/Speed

⇒ t₂ = 0.9/9

⇒ t₂ = 0.1 h

________________________________

Total time taken (in hours) :-

= t₁ + t₂

= (0.15 + 0.1) h

= 0.25 h

Total time taken (in minutes) :-

⇒ 1 hour = 60 mins

⇒ 0.25 hour = 0.25 × 60

⇒ 15 mins

Answer 2

Explanation :-We have :-• Speed during first journey = 6 km/h• Speed during return journey = 9 km/h• Distance = 900 m = 0.9 kmFor first journey :-⇒ Time = Distance/Speed⇒ t₁ = 0.9/6⇒ t₁ = 0.15 hFor return journey :-⇒ Time = Distance/Speed⇒ t₂ = 0.9/9⇒ t₂ = 0.1 hTotal time taken (in hours) :-= t₁ + t₂= (0.15 + 0.1) h= 0.25 hTotal time taken (in minutes) :-⇒ 1 hour = 60 mins⇒ 0.25 hour = 0.25 × 60⇒ 15 mins