Physics, asked by naveen876, 10 months ago

A man goes to market 2km away with velocity 20 m/s.He returned with velocity 10 m/s Find the magnitude of average velocity and average speed of the man​

Answers

Answered by deepsen640
2

Answer:

Average velocity = 0 m/s

Average speed = 13.3 m/s

Step by step explanations :

Given that,

A man goes to market

2km away with velocity 20 m/s

.He returned with velocity 10 m/s

let the velocity with going market be V1

and returning velocity be V2

here,

V1 = 20 m/s

time taken = 2000/20

= 100 s

V2 = 10 m/s

time taken = 2000/10

= 200 s

distance of market from him = 2 km

= 2000 m

Average velocity = displacement /time

here,

displacement of him = m

because he returns to his initial position

so,

Average velocity = 0 m/s

now,

Average speed

= total distance travelled/time taken

here total distance travelled = 4000 m

total time taken = 100 + 200 s

= 300 seconds

putting the values,

Average speed = 4000/300

= 13.3 m/s

so,

Average speed = 13.3 m/s

________________

Average velocity = 0 m/s

Average speed = 13.3 m/s

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