Question

A man got 20% increase in his salary. If his new salary is Rs. 1,86,000, find his original

salary.​

Answer 1

$\huge\sf\mathbb\color{ye} \underline{\colorbox{white}{☯SoLuTiOn☯}}$

Let the salary before the increment be Rs.100 Then,

Increase in salary = Rs. 20

∴ Increase salary is Rs.120, Original salary = Rs. 100

If interested salary is Rs.1,86,000. Original salary

$= Rs.( \frac{100}{120} \times 186 , 000) = Rs.155 ,000 \\ </p><p>$

Hence, the salary of the man before increment was Rs. 1,55,000

Answer 2

Given,

• Increase percentage = 20%
• New salary = 1,86,000

Let the original salary be X

Now,

New salary = originally salary + increase in salary

➾ 1,86,000 = x + increase in salary

➾ 1,86,000 - x = increase in salary

Increase in salary = 1,86,000 - x

Now,

$\underline{\boxed{ \sf{ \red{Percentage \: increase = \frac{increase \: salary }{original \: salary} × 100}}} }$

$\sf \: ⟼20 = \frac{186000 - x}{x} \times 100 \\ \\ \sf \: ⟼20x = (186000 - x) \times 100 \\ \\ \sf \: ⟼ \frac{20x}{100} = 186000 - x \\ \\ \sf \: ⟼ \frac{2x}{10} = 186000 - x \\ \\ \sf \: ⟼ \frac{2x}{10 } \times x = 186000 \\ \\ \sf \: ⟼ \frac{2x}{10} = 186000\\ \\ \sf \: ⟼x \bigg( \frac{2}{10} + 1 \bigg) = 186000 \\ \\ \sf \: ⟼x \bigg( \frac{2 + 10}{10} \bigg) = 186000 \\ \\ \sf \: ⟼x \bigg( \frac{20}{10} \bigg) = 186000 \\</strong><strong>\</strong><strong>\</strong><strong> \sf \: ⟼x = \frac{186000 \times 10}{20}\\</strong><strong>\\ </strong><strong>\sf \: ⟼x=\frac{186000}{20}</strong><strong>\</strong><strong>\</strong><strong>\</strong><strong>\</strong><strong>\sf \: ⟼x =93000$

Therefore, Original salary is Rs. 93000