Math, asked by Riddhima5459, 10 months ago

a man had rupees 15,000 he gave two fifth of the amount to his wife and divided the rest among his three sons in the ratio of 2:3:5 how much did each of his son get ​

Answers

Answered by Harshbarasia
0

Answer:

2/5 *15000

6000

wife gets 6000 RS

total amount son get 15000-6000

9000

let the ratios be in x

then 2x + 3x + 5x =9000

10x=9000

x=900

first son= 2x = 2 * 900=1800

second son=3x=3* 900=2700

third son = 5x = 5* 900= 4500

Answered by apurvnandan2005
0

Answer:

2/5 of 15000 = 6000

so 15000-6000= 9000 to be distributed among three children.

let x is common factor in this ratio

so 2x+3x+5x = 9000

10x=9000

x= 900

so Rs 1800, 2700 & 4500 his three Sons will get.

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