Question

A man has 2 daughters and 1 son. the sum of the ages of his two daughters and 1 son is equal to the age of the father. in 15 years, the sum of the ages of his children will be one and half times their father's age then.what is the fathers age now?

Answer 1

Let us assume present age of Father is x years and a, b are the ages of his daughter and c is the age of his son.

Given:

x = a + b + c -------------1

Also given:

In 15 years,

a + 15 + b + 15 + c + 15 = 1 1/2  * (x + 15)

a + b + c + 45 = 3/2 *( x + 15)

 (a + b + c) + 45 – 45/2 = 3/2 x  ---------------2

Multiply the equation on both sides by 2

2(a + b + c) + 90 – 45 = 3x

Substitute the value of x = a + b + c from equation 1 in equation 2

2x + 45 = 3 x

x = 45 years

The present age of Father is 45 years.