Math, asked by mohantalinky9232, 1 year ago

A man has 3 sons 1st one & 2nd one can complete a work in 24 days and 36 days respectively. In how many days the 3rd son will complete the work, if the man could alone complete the whole work in 36/11 days. The man can do double work in same time . In what time all his sons together can complete the work.

Answers

Answered by amitnrw
20

Answer:

4.5 Days

Step-by-step explanation:

1st one & 2nd one can complete a work in 24 days and 36 days respectively

1st son 1 day work = 1/24

2nd son 1 day work = 1/36

man could alone complete the whole work in 36/11 days

=> Man 1 Day work  = 11/36

The man can do double work in same time

=> 3rd son 1 Day work = 11/72

All three son 1 day work  = 1/24 + 1/36 + 11/72

= (3 + 2 + 11)/72

= 16/72

= 2/9

all his sons together can complete the work in 9/2 Days

= 4.5 Days

Answered by jitendarnunia
5

Answer:

12 days

Step-by-step explanation:

AK like to banta ha ☺

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