A man has certain number of small boxes to pack into parcels .If he packs 3,4,5,or 6 in a parcel he left with one .if he packs 7 in a parcel , none is left over.What is the number of boxes he has to pack ?
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Answered by
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The man has 301 small boxes. It is the smallest number which can be divided by 3,4,5,6 with remainder 1 and is completely divisible by 7.
The LCM of 3,4,5,6 is 60.
We have to find the least multiple of 60 which when added with 1 can be completely divisible by 7.
This case is satisfied by 300.
When we add 1 to 300
300+1=301
Divide by 7, it's 301/7 = 43.
So if he has to pack 301 boxes and packs 3,4,5,6 box he is left with one and if he packs 7 boxes he is left with no box.
The LCM of 3,4,5,6 is 60.
We have to find the least multiple of 60 which when added with 1 can be completely divisible by 7.
This case is satisfied by 300.
When we add 1 to 300
300+1=301
Divide by 7, it's 301/7 = 43.
So if he has to pack 301 boxes and packs 3,4,5,6 box he is left with one and if he packs 7 boxes he is left with no box.
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Answered by
9
Answer:
301 boxes
Step-by-step explanation:
The number should be divisible by 3,4,5,6. And leave the remainder 1 but it should be completely divisible by 7 . So LCM of 3,4,5,6 is 300 and if we add 1 that it divisible by 7. So it is correct that answer is 301.
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