Question

a man has some chocolates to distribute among 4 kids he gives half of the number of the chocolates plus 1 to the first kid one seventh of the remaining chocolates plus 3 to the second kid and one third of the remaining chocolates plus 2 to the third kid he furthur gives remaining 4 chocolates to the fourth kid

Answer 1

Answer:

The remaining chocolates left after distributing 100 chocolates is 20 chocolates .

Step-by-step explanation:

Given as :

Let The number of chocolates does man have = 100

'n ' number of chocolate are distributed among 4 kids

First kid

half number of chocolates + 1

i.e $\dfrac{100}{2}$+ 1                              

       50 + 1 = 51                             ..........A

First kid were get 51 chocolates

Now, The remaining chocolate = 100 - 51 = 49

Second kid

$\dfrac{1}{7}$ th of remaining + 3

i.e 49 × $\dfrac{1}{7}$ + 3

i.e 7  + 3 = 10                ..........B

Second kid were get 10 chocolates

The remaining 49 - 10 = 39

Third kid

$\dfrac{1}{3}$ rd of remaining + 2

i.e $\dfrac{1}{3}$ × 39 + 2

Or, 13 +2 = 15

Third kid were get 15 chocolates

So, the left chocolates = 39 -15 = 24

Fourth kid were get 4 chocolate

So, At last the remaining chocolates = 24 - 4 = 20

Hence, The remaining chocolates left after distributing 100 chocolates is 20 chocolates . Answer