Question

A man has some hens and some cows. if the number of heads is 50 and number of feet is 142. the number of cows is

Answer 1

Let no. of cows be x

Then no. of hens = 50-x

No. of feet of cows =4×x (cows have 4 legs each)

No. of feet of hens=(50-x)×2 (hens have 2 legs each)= 100-2x

Total no. of feet=4x+(100-2x)=4x+100-2x=100+2x

But,A.T.Q Total no. of feet=142

So, 100+2x=142
= 2x=142-100
= 2x=42
= x=42/2=21

So,the no. of cows is 21.

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