Question

A man has three times as old as his son. Eight years ago the man was seven times as old as his son. Find their present ages

Answer 1

Let Son's age = x
Then Man's age = 3x
Man's age 8 yrs ago = 3x – 8
Son's age 8yrs ago = x – 8
Hence 3x – 8 = 7 × (x–8)
3x–8 = 7x–56
4x = 48
x = 12
Therefore
Son's and man's present ages are 12yrs and 3×12yrs = 36yrs respectively