a man has to do a piece of work in 3 days. he completed one by sixth of it on the first day and seven by 10th of the reminder on the second day. what fraction of piece of work is done on the third day
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A can complete 1/3rd of a work in 5 days. So A completes the work in 5×1÷1/3=15days. In one day A completes 1/15th part of work. B can complete 2/5 th part of a work in 10 days. So B completes the work in 10×1÷2/5=50/2=25 days. In 1 day B completes 1/25th part. Both A & B complete jointly 1/15+1/25=8/75 th part of work. Now, to complete the work they jointly will take 75/8 days=9 days 9 hours.
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