A Man has to go 50due to north,4 0 due east amd 20 m to south find the distance he has to walk to reach final point
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Explanation:
Distance :
Distance is the total path covered by the man.
Distance travelled by man=50m+40m+20m=110m
Displacement :
Displacement is the shortest path between source [house] and destination [ field]= AB
See the figure :
Draw Perpendicular BE to AC.
BE=CD=40m
AE=AC-CE=50-20=30
NOW, DISPLACEMENT AB=√AE²+EB²
AB=√30²+40²=50m
Angle with horizontal is given by tanθ=30/40=3/4
θ=tan⁻¹[3/4] direction north to east.
∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.
HOPE IT HELPS!!!
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