Question

A man has two daughters and one son. The sum of the ages of his two daughters and one son is equal to age of the father. In 15 years the sum of the ages of his children will be 1 and half times their father's age. What is the father's age now

Answer 1

Let the age of father be x years.
So the sum of 2sons and a daughter will be x years too as given.
After 15 year.
Father's age = x+15.
Sum of two sons and daughter's age = x+15+15+15(as their are two sons and daughter)

So x+45= 1.5(x+15)

x+45= 1.5x + 22.5

1.5x-x= 45-22.5

0.5x = 22.5

x= 22.5/0.5

x= 45.

Hope it helps.

Answer 2

Father's age now is 45 years.

Step-by-step explanation:

Let the age of age of daughters be 'x' and 'y'. The age of son be 's' and the age of father be 'f'.

Now,     according to question

                               ⇒ x + y + s = f      .........      (1)

Now, 15 years later,

                                  ⇒ x + 15 + y + 15 +  s + 15 = (f + 15) x 1.5

                                  ⇒ x + y + s + 45 = 1.5 x f + 22.5

                                 

Put the value of equation (1) ot above equation.

                                   ⇒ f = 1.5 x f + 22.5

                                    ⇒ 0.5 x f = 22.5

                                    ⇒ f = 45 years