Math, asked by dipankarnmc, 2 months ago

A man having spent 2/13 ths of his money found that he had Rs. 44 left. How much had he at first?​

Answers

Answered by rnaik6822
0

Answer:

Let the money with the man originally be x.

Given the man spends 3/8 of his money and still had 720 left with him,

=> x - (3/8)x = 720

=> [1–(3/8)]x = 720

=> (5/8)x = 720

=> x = (720 * 8)/5 = 1152

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