Question

"A man hired a taxi to reach his office. 10 km away from home. The driver followed a long
& take 1 hory and charged from the man for 25kin.
Q11(A) - Average speed of taxi is
(i). 25km/h (ii). 10km/h (iii). 2.5k (iv). 250km/h
(B) - Average velocity of car in km/h is
(1). 25x10
(). 25/10 (iii). 25 (iv). 10
(C)- Extra distance travelled by man in km is
(1). 15
(ii). 23
(iii). 10 (iv). Zero
(D) -- Extra displacement of man in km is
(1). 15 (ii). 25 (ii). 10 (iv). zero
(E) - Actual displacement in km is
(i). 15 (11). 25 (iii). 10 (iv). Zero
Section - C​

Answer 1

Given :

Distance = 25km

Time = 1 hour

Displacement = 10km

Solution:

(A) Average speed of taxi = Total distance travelled / Total time

                                           =   $\frac{25}{1} = 25 km/hour$

Therefore (i) is the correct option

(B) Average velocity of the car = total displacement / total time

                                                     = $\frac{10}{1} = 10 km/hour$

Option (iv) should be correct

(C) Extra distance travelled by man will be $25-10 = 15km$

(D) Extra displacement in km is not defined.

(E) Actual displacement in km is the shortest distance travelled which is 10km i.e. option (iii)