Question

A man hits a golf ball ( mass = 0.2 kg ) which accelerates at the rate of 20 meters/ second square. What amount of force is acted on the bell ( F = m x a )

Answer 1

F=m*a
F=0.2 x 20=4 N
Hope it helped u

Answer 2

F = m*a
F =(0.2*20)kg.meters/second square
F(force acted on the body) = 4kg.meters/second square
                                            =or 4N (newton)