A man in a balloon rising vertically with an acceleration of 4.9 m/ s 2 second after the balloon is let go from the ground the greatest height above the ground reached by the ball is ( g = 9.8 2 )
Answers
Answered by
6
Answer:
a=4.9㎨
Initial velocity =0
Velocity of balloon and ball after 2 sec
v=u+at=9.8㎧
Height at this point
h=
2
1
at
2
=0.5×4.9×4
=9.8m
The ball will attain further height =s
2
1
mv
2
=mgs
s=
2g
v
2
=4.9m
Greatest height that can be achieved
H=h+s=9.8+4.9=14.7m
Explanation:
Hope it helps.
If it helps mark as brianliest.
Answered by
0
Answer:
udhdjxjsjsxjj
Explanation:
jdjjsjzhzjsjjxjjGjiisjwjsjwk
Similar questions