Physics, asked by mtbcd09, 1 year ago

a man in a balloon rising vertically with an aceeleration of 4.9 meter per second square releases a ball 2 seconds after the balloon is let go from the ground. The greatest height above the ground reach by the ball is (g= 9.8 meter per second square)

Answers

Answered by shijoarobert
3
Height travelled by balloon=(1÷2)at^2 Intial velocity of ball=at(inertia of motion) Extra height travelled by ball=(at)^2÷2g Total height=height travelled by ballon+extra height travelled by ball
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