A man invest 1/3 of his capital at 7%,1/4 at 8% and remainder at 10%.If his annual income rs 561,the capital is
Answers
Answered by
24
Answer:
Let the capital be Rs. P, then
(P/3) x (7/ 100) + (x/4) x (8/100) + [P - (P/3 + P/4)] x 10/100 = 561
⇒ 7P/300 + P/50 + P/24 = 561
⇒ 42P + 36P + 75P = 1009800
P = 1009800/153 = 6600
Answered by
0
Step-by-step explanation:
1/3 of 561= 187 so she invest 187 at 7%
now
561-187=364
so 1/4 of 364= 1/4×364=91
so now
she invest 187 at 7% and 91 at 8%
187+91=278
7%of187=12.97 and 8%of 91 is 7.28
so
278+12.97+7.28-561=263
now
263-20( 12. 97+7. 28)=243 ans
now
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