Question

A man invest 1/3 of his capital at 7%,1/4 at 8% and remainder at 10%.If his annual income rs 561,the capital is

Answer 1

Answer:

Let the capital be Rs. P, then

(P/3) x (7/ 100) + (x/4) x (8/100) + [P - (P/3 + P/4)] x 10/100 = 561

⇒ 7P/300 + P/50 + P/24 = 561

⇒ 42P + 36P + 75P = 1009800

P = 1009800/153 = 6600

Answer 2

Step-by-step explanation:

1/3 of 561= 187 so she invest 187 at 7%

now

561-187=364

so 1/4 of 364= 1/4×364=91

so now

she invest 187 at 7% and 91 at 8%

187+91=278

7%of187=12.97 and 8%of 91 is 7.28

so

278+12.97+7.28-561=263

now

263-20( 12. 97+7. 28)=243 ans

now