Question

A man invested 1/3 of his capital at 7% 1/4 at 8% and the remainder at 10%. If his monthly income is Rs. 561, the capital is. A) 6600 B) 79200 C) 13200 D) 6732

Answer 1

SOLUTION:-

let the capital amount be x

=> 7% of x/3 = 7x/300

=> 8% of x/4 = 8x/400 = x/50

=> 10 % of remaining [ x-(x/3+x/4)]

= 10% of 5x/12 = 50x/1200

= x/24

total income = 7x/300+x/50+x/24 = 561. (given)

=> (14x+12x+25x) = 561×600

=> 51x = 561×600

=> x = 561×600/51

= 11×600

= 6600

=> Capital amount (x) = 6600

=> option (a) 6600 is the correct option.

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