Math, asked by vaishnavi9573, 8 months ago

A man invested Rs 40,000 for 3years at the compound interest rate 8% per anumm.. After 2 years the rate of intrest was raised to 10%
1:find the total interest earned by him.
2:find the amount he recieved after 3 years ​

Answers

Answered by Angie432
2

Answer:

Step-by-step explanation:

1.Interest = \frac{PRT}{100}

P =40,000

R = 10%

T = 2 years

I = \frac{40,000  * 10 * 2}{100}

  = 400 * 10 * 2

  = 400 * 20

  = 8000

2. Interest = \frac{PRT}{100}

P =40,000

R = 10%

T = 3 years

I = \frac{40,000  * 10 * 3}{100}

  =  4000 * 3

   =  12000

Amount = 40, 000 + 12,000

              =  52,000.

HOPE IT HELPS!!!!!!!!!!!!

Answered by jeffwin18
2

Answer:

1.Interest = \frac{PRT}{100}

100

PRT

P =40,000

R = 10%

T = 2 years

I = \frac{40,000 * 10 * 2}{100}

100

40,000∗10∗2

= 400 * 10 * 2

= 400 * 20

= 8000

2. Interest = \frac{PRT}{100}

100

PRT

P =40,000

R = 10%

T = 3 years

I = \frac{40,000 * 10 * 3}{100}

100

40,000∗10∗3

= 4000 * 3

= 12000

Amount = 40, 000 + 12,000

= 52,000.

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