Math, asked by arthakur, 7 months ago

a man invested rupees 10000 in the bank for 3 upon two year at the rate of 15% per annum compounded annually find the amount he will you received at the end of the period​

Answers

Answered by anamika851
0

Answer:

Principal= Rs. 10,000

Time= 3/2 year

Rate of Interest= 15%

Simple Interest=

 \frac{p \times r \times t}{100}  \\  = \frac{10000 \times 15 \times 3}{100 \times 2}  \\  =  \frac{4500}{2}  \\  = 2250

Simple Interest= Rs. 2250

Amount = Simple Interest + Principal

 = 10000 + 2250 \\  = 12250

So, the amount = Rs. 12250

Hope this may help you

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Answered by AswinMony
0

Answer:

Rs.12362.50

Step-by-step explanation:

(P) Principal = Rs.10000

(t) Time period = 3/2 years or 1 and 1/2 years

(r) Rate = 15% per annum (compounded annually)

(n) Number of times compounded in a time period

(A) Amount = P(1+r/(100*n))^n*t

Therefore, Amount = 10000(1+15/100)(1+15/200)

= 10000(115/100)(215/200)

= Rs.12362.50

Hope this is helpful :)

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