a man is 24 year older than his son if the sum of their presence age is 60 years. find the age of sin and father
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Answered by
0
Answer:
Let the present age of son be x.
Then, present age of father is (60−x).
According to the question,
⇒ (60−x)−6=5(x−6)
⇒ 54−x=5x−30
⇒ 54+30=5x+x
⇒ 84=6x
⇒ x=
6
84
⇒ x=14
∴ Son's age after 6 years =(x+6)years
=(14+6)years
=20years.
Answered by
0
Answer:
Let the present age of son be x.
Then, present age of father is (60−x).
According to the question,
⇒ (60−x)−6=5(x−6)
⇒ 54−x=5x−30
⇒ 54+30=5x+x
⇒ 84=6x
⇒ x=
6
84
⇒ x=14
∴ Son's age after 6 years =(x+6)years
=(14+6)years
=20years.
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