a man is 24 years older than his son. 12 years ago he was five times age of his son .find their Present ages.
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Let the ages of the father and son be x and y respectively.
Then, x = y + 24.
Twelve years ago, father was 5 times son's age.
x-12 = 5 * (y -12)
Substituting the value of x = y + 24 in the above equation, we get
y + 24 = 5y - 60
or 5y - y = 60 + 24
4y = 84
Therefore, y = 84/4 = 21.
and x = 21 + 24 = 45.
Therefore, the father's age is 45 and son's age is 21.
Then, x = y + 24.
Twelve years ago, father was 5 times son's age.
x-12 = 5 * (y -12)
Substituting the value of x = y + 24 in the above equation, we get
y + 24 = 5y - 60
or 5y - y = 60 + 24
4y = 84
Therefore, y = 84/4 = 21.
and x = 21 + 24 = 45.
Therefore, the father's age is 45 and son's age is 21.
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