Math, asked by krisharam1069, 1 year ago

A man is 24 years older than his son. After two years, his age will be three times that of his son. Find their present ages.

Answers

Answered by avinashsingh48
14
hey mate here is your answer

let the son age be X

and Father age be X+24

after two years

son age will be X +2

and Father age will be X + 24+2

according to your question

X + 24+2= 3(X+2)

X -3x = -26+6

 - 2X= - 20

 X= -20/-2

X = 10

their present ages are

son age = 10 years

father age =24 +10 =34 years

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Answered by Anonymous
22

Answer:

Let the sons present Age be x years.

Then, Mans present age will be (x + 24) years.

According to Question :

➳ x + 24 + 2 = 3(x + 2)

➳ x + 26 = 3x + 6

➳ 26 - 6 = 3x - x

➳ 2x = 20

➳ x = 10 years

Therefore,the present age of his son is 10 years.

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