Question

In the given figure, ABCD is a parallelogram. Find x, y and z.​

Answer 1

X=180-125=55

Y=180-55=125

Z=180-125=55

Answer 2

Here, ∠DAC = 125°

∠ADC = x

∠DCE = y

∠AEC = z

∠ECB = 56°

Given, ABCD is a parallelogram

∴ ∠DAB = ∠DCB

∠DAB = ∠DCE + ∠AEC

{∵ ∠DCB = ∠DCE + ∠AEC}

125° = y + 56°

y = 125° - 56°

y = 69°

Now, In Parallelogram ABCD ,

∠DAB + ∠ADC = 180°

125° + x = 180°

x = 180° - 125°

x = 155°

As, ABCD is a parallelogram,

AB || DC

& EC is transversel

∴ ∠DCE + ∠AEC = 180°

y + z = 180°

69° + z = 180°

z = 180° - 69°

z = 111°

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