A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
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Answered by
12
Let the son's present age be x years.
Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
Then, man's present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22
Answered by
3
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22.
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