Math, asked by camlin, 1 year ago

a man is 24 yes older than his son. 12 yrs ago he was 5times as old as his son. Find the ages of both

Answers

Answered by MikeTomlinson
3
Son's age be x years
Man's age will be x + 24 years

12 years ago,
Son's age = x - 12 years
Man's age = x + 24 -12 = x + 12 years

According to the condition given,
x + 12 = 5(x - 12)
x + 12 = 5x - 60
x - 5x = -60 - 12
-4x = - 72
x = 72/4
x = 18

In short, your Answer is Son's age = 18 years
Man's age = 18+24 = 42 years

Hope this helps !
Answered by SARDARshubham
1
Let the man's age be x years ,
and the age of his son be y years ;

According to the question

x = y+24 -----–-(1)

(x-12) = 5×(y-12)
x-12 = 5y-60
x = 5y-48 ------(2)

On comparing equation (1) & (2), we get ;

y+24 = 5y-48
5y-y = 24+48
4y = 72
y = 18

x = y+24
x = 18+24
x = 42
________________
Hence the present age of the man is 42 years and that of his son is 18 years
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