Question

A man is 26 years older than his son. In five years their ages will total 70. What are their present age​s.​

Answer 1

17,43

Step-by-step explanation:

m=s+26

in 5years,

(s+5)+(m+5)=70

s+m+10=70

s+m=60

substituting,

s+26+s=60

2s=34

s=17

then,

m=17+26

m=43

Answer 2

$\huge\underline\bold{ \sf \: GiveN :-}$

A man is 26 years older than his son.

After 5 years the sum of their ages will be 70.

$\huge\underline\bold{ \sf \: To \: FinD :-}$

Their present ages.

$\huge\underline\bold{ \sf \: SolutioN:-}$

${\sf \: Let,}$

the present age of son be x years . Then,

the present age of father = (x + 26) years.

${\sf \: after \: 5 \: years \: the \: age \: of \: }$

Father = (x + 26) + 5 = x + 31

Son =x + 5

A/q

After 5 years the sum of their ages will be 70.

${\sf \ \implies \: (x+ 31) + (x + 5) = 70 }$

${\sf \ \implies \:x + x + 31 + 5 = 70 }$

${\sf \ \implies \: 2x + 36 = 70 }$

${\sf \ \implies \: 2x = 70 - 36 }$

${\sf \ \implies \: 2x = 34 }$

${\sf \ \implies \: x = \frac{34}{2} }$

${\sf \ \implies \:x = 17 }$

${ \boxed{∵x = 17}}$

By putting the value of x

present age of father = (x + 26) years

= ( 17 + 26 ) years

= 43 years

the present age of son = x years

= 17 years

Therefore , the present age of father and his son is 43 years and 17 years respectively.