Question

A man is 26 years older than his son. Three years hence, he will be three times as old as his son. What is the present age of the father?

Answer 1

Step-by-step explanation:

Let the age of son be x then age of father =x+26

ATQ, After three years, x+26+3=3(x+3)

x+29=3x+9

=>2x=29-9=20

=>x=20/2=10.

Present age of father=x+26=10+26=36.

Answer 2

The father's present age is 39 years.

• An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
• Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information, we are given that,

A man is 26 years older than his son.

Let the the son's age be x.

Then, the man's age is $x+26$.

Now, after 3 years, he will be $3x$.

Then, we get,

$(x+23) +3 =3x$

Or, $x+26 = 3x$

Or, $2x = 26$

Or, $x = 13$.

Then, the present age of the man is $x+26 = 13+26 = 39.$

Hence, the father's present age is 39 years.

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