Question

A man is 28 years older than his son after 10 years he will be thrice as old as his son find thier present ages

Answer 1

Let the man's age be 'x' and
      his son's age be 'y'.
Given the man is 28 years older than his son,
                  x=28+y→1
FUTURE:
After 10 years, he'll be thrice the old as his son.
 ∴x+10=3(y+10)
   x+10=3y+30
    x-3y=30-10
    x-3y=20
Substituing this in 1, we get:
28+y-3y=20
        -2y=20-28
        -2y=-8
            y=-8÷-2
         ⇒y=4.
Substituting this in 1, we get:
          x=28+y
            =28+4
         ∴x=32.
∴The present age of the man is 32 years and his son's is 4 years.





Hope this helps.. c:

Answer 2

Answer:

Let present age of son = x years

So, present age of father = x + 28 years,

After 10 years,

Age of son = x + 10 years

and age of father = x + 28 + 10 = x + 38 years,

Given that, after 10 years, age of father will be thrice as old as his son

=> x + 38 = 3(x + 10)

=> x + 38 = 3x + 30

=> 38 = 3x + 30 - x

=> 38 = 2x + 30

=> 2x = 38 - 30

=> 2x = 8

=> x = 8/2

=> x = 4

So, present age of son = x = 4 years

and present age of father = x + 28 = 4 + 28 = 32 years,

Step-by-step explanation:

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