Question

A man is 3 times as old as his son .after 15 years,he will be only twice as old as his son.find their present ages​

Answer 1

Answer:

the son's age is 15

Step-by-step explanation:

Let the present age of son be x years  

Then, present age of other =3x years

After 15 years :

Son's age =(x+15) years

Father's age =(3x+15) years

But, according to the question.

⇒(3x+15)=2(x+15)

⇒3x+15=2x+30

⇒3x−2x=30−15

⇒x=15

Answer 2

Answer:

Let the present age of son = x years

Then, present age of other = 3 years

After 15 years:

Son's age = (x+15) years

Father's age = (3x+15) years

but , according to question:

(3x+15) = 2(x+15)

3x + 15 = 2x + 30

3x-2x = 30 - 15

x = 15

→ Son's age is 15 years.