Math, asked by Raju11143, 1 year ago

A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. find their present ages.

Answers

Answered by Panzer786
11
Heya !!




Let the present age of son be X years.



Age of father = 3X.




After 15 years age of son = ( X + 15 ) years


After 15 years age of father = ( 3X + 15 ) years

According to the question,



3X + 15 = 2 ( X + 15)


3X + 15 = 2X + 30


3X - 2X = 30 - 15



X = 15 years



Present age of son = X = 15 years


And,


Present age of father = 3X = 3 × 15 = 45 years.
Answered by Shreya1429
3
Hey friend! Here is your answer.

Let the son's present age be x.

Father's present age = 3x

After 15 years,

Son's age = x+15

Father's age = 3x + 15

According to the question,

3x+15=2(x+15)

3x+15=2x+30

3x-2x=30-15

x=15

Son's present age = 15 years

Father's present age = 3x

= 3×15

=45 years
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