A man is 3 times as old as his son. After 15 years, he will be only twice as old as his son. find their present ages.
Answers
Answered by
11
Heya !!
Let the present age of son be X years.
Age of father = 3X.
After 15 years age of son = ( X + 15 ) years
After 15 years age of father = ( 3X + 15 ) years
According to the question,
3X + 15 = 2 ( X + 15)
3X + 15 = 2X + 30
3X - 2X = 30 - 15
X = 15 years
Present age of son = X = 15 years
And,
Present age of father = 3X = 3 × 15 = 45 years.
Let the present age of son be X years.
Age of father = 3X.
After 15 years age of son = ( X + 15 ) years
After 15 years age of father = ( 3X + 15 ) years
According to the question,
3X + 15 = 2 ( X + 15)
3X + 15 = 2X + 30
3X - 2X = 30 - 15
X = 15 years
Present age of son = X = 15 years
And,
Present age of father = 3X = 3 × 15 = 45 years.
Answered by
3
Hey friend! Here is your answer.
Let the son's present age be x.
Father's present age = 3x
After 15 years,
Son's age = x+15
Father's age = 3x + 15
According to the question,
3x+15=2(x+15)
3x+15=2x+30
3x-2x=30-15
x=15
Son's present age = 15 years
Father's present age = 3x
= 3×15
=45 years
Let the son's present age be x.
Father's present age = 3x
After 15 years,
Son's age = x+15
Father's age = 3x + 15
According to the question,
3x+15=2(x+15)
3x+15=2x+30
3x-2x=30-15
x=15
Son's present age = 15 years
Father's present age = 3x
= 3×15
=45 years
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