Math, asked by Nasir1111, 1 year ago

5 under root + 3 under root / 5 under root - 3 under root

Answers

Answered by ishwarsinghdhaliwal
0

\frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}   -   \sqrt{3} }  = x \\ \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}   -   \sqrt{3} } \times \frac{ \sqrt{5}  +  \sqrt{3} }{ \sqrt{5}    +   \sqrt{3} } = x \\  \frac{( \sqrt{5} ) ^{2}  +(  \sqrt{3} ) ^{2}  + 2 (\sqrt{5})( \sqrt{3}  )}{( \sqrt{5}) ^{2}  - ( \sqrt{3}) ^{2}   }  = x \\  \frac{5 + 3 + 2 \sqrt{15} }{5 - 3}  = x \\  \frac{8 + 2 \sqrt{15} }{2}  = x \\  \frac{2(4 +  \sqrt{15}) }{2}  = x \\ 4 +  \sqrt{15 }  = x
Answered by reemaanver999
0

Hope this helps.... plz mark as brainliest...

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reemaanver999: Plz mark as brainliest...!
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