Question

A man is 3 times as old as his son. after 15 years , he will be only twice as old as his son. Fins their present age

Answer 1

Answer:

Man's present age = 45 yrs.

Son's present age = 15 yrs.

Explanation:

Given,

A man is 3 times as old as his son.

Assuming his son's present age as $\boldsymbol x$ yrs.

∴ Man's age = $\boldsymbol {3x}$ yrs.

Now,

15 years later,

• Man's age = $\boldsymbol {(3x + 15)}$ yrs.
• Son's age = $\boldsymbol {(x + 15)}$ yrs.

According to the question,

$\implies (3x + 15) = 2(x + 15)$

$\implies 3x + 15 = 2x + 30$

$\implies 3x - 2x = 30 - 15$

$\implies x = 15$

∴ Son's present age is 15 years.

Henceforth,

Man's present age is:-

$= 3x$

$= 3(15)$

$\bf = 45 \: years$

__________________________

Answer 2

Answer:father is 45 and son is 15

Step-by-step explanation:Take the father's age at f, the son's age as s.

f = 3s

f + 15 = 2(s + 15) = 2s + 30, so f = 2s + 15

3s = 2s +15

s = 15

f = 45

The father is 45, the son is 15.