Math, asked by vasu42, 1 year ago

a man is 3 times as old as his son.after 15yr he will be only twice as old as his son. find their present ages

Answers

Answered by Bunti360
4
let the age of son be x,
now , the age of father = 3x,

After 15 years,

(3x+15) = 2(x+15)

3x + 15 = 2x + 30

x = 15,

3x = 3*15 = 45,

Therefore,
Present age of the man = 45 years,
Present age of his son = 15 years,

Hope you understand !!
Answered by aryan1191
2
let the present age of man be X
and son be Y
A.T.Q
x=3y...1
after 15 years
x+15=2(Y+15)
x-2y=15......2
putting value 1 in 2
3y-2y=15
Y=15
putting in 1
x=3×15
x=45
man=45
son=15
HOPE it helps you
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