a man is 3 times as old as his son.after 15yr he will be only twice as old as his son. find their present ages
Answers
Answered by
4
let the age of son be x,
now , the age of father = 3x,
After 15 years,
(3x+15) = 2(x+15)
3x + 15 = 2x + 30
x = 15,
3x = 3*15 = 45,
Therefore,
Present age of the man = 45 years,
Present age of his son = 15 years,
Hope you understand !!
now , the age of father = 3x,
After 15 years,
(3x+15) = 2(x+15)
3x + 15 = 2x + 30
x = 15,
3x = 3*15 = 45,
Therefore,
Present age of the man = 45 years,
Present age of his son = 15 years,
Hope you understand !!
Answered by
2
let the present age of man be X
and son be Y
A.T.Q
x=3y...1
after 15 years
x+15=2(Y+15)
x-2y=15......2
putting value 1 in 2
3y-2y=15
Y=15
putting in 1
x=3×15
x=45
man=45
son=15
HOPE it helps you
and son be Y
A.T.Q
x=3y...1
after 15 years
x+15=2(Y+15)
x-2y=15......2
putting value 1 in 2
3y-2y=15
Y=15
putting in 1
x=3×15
x=45
man=45
son=15
HOPE it helps you
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