Math, asked by CHSURYASASIDHAR2088, 10 months ago

A MAN IS 3 TIMES AS OLD AS IS SON AFTER15 YEARS HE WILL BE TWICE AS OLD AS HIS SON FIND THEIR PRESENT AGES

Answers

Answered by navadeepsai11
16

Answer:

Let the age of son = x.

Then the age of man will be 3 times as old as his son = 3x.

After 15 years:

Age of son = x + 15.

Age of man = 3x + 15.

Given that Man will be only twice as old as his son.

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x = 2x + 15

x = 15.

Therefore the age of son = 15 years.

the age of man = 45 years.

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Answered by BrainlyRaaz
13

Given :

  • A man is 3 times as old as his son.

  • After 15 years he will be twice as old as his son.

To find :

  • Their present ages =?

Step-by-step explanation :

Let, the present age of son be x.

Then, the present age of man be 3x.

After 15 years son's age = x + 15

After 15 years man's age = 3x + 15

According to the question :

➮ 3x + 15 = 2(x + 15)

➮ 3x + 15 = 2x + 30

➮ 3x - 2x = 30 - 15

➮ x = 15

Therefore, We got the value of, x = 15.

Hence,

Present age of the son, x = 15 years.

And Present age of man, 3x = 3 × 15 = 45 years.

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