a man is 3 times old as his son. after 15 years , he will only be twice as old as his son . find their preseny ages
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Answered by
3
Answer:
Step-by-step explanation:
let the present age of the son be x so the present age of the man = 3x
After 15 years,
age of son = x+15 and age of man = 3x+15
given,
3x + 15 = 2(x+ 15)
3x + 15 = 2x + 30
3x - 2x = 30 - 15
x = 15 and y = 3x = 3* 15= 45
so the present age of man is 45 years and the present age of son is 15 years
Answered by
4
Given:-
- A man is 3 times old as his son. after 15 years , he will only be twice as old as his son.
To find:-
- Present of Man and his son
Solution:-
Let the age of son be x years
Then the age of man will be 3 times as old as his son = 3x
★ After 15 years
- Age of son = x + 15
- Age of man = 3x + 15
According to question,
Man will be only twice as old as his son.
3x + 15 = 2(x + 15)
3x + 15 = 2x + 30
3x = 2x + 15
3x - 2x = 15
x = 15
Therefore,
★ The age of Son (x) = 15 years
★ The age of Man ( 3x ) = 3 × 15 = 45 years
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