Math, asked by sehran126226, 9 months ago

a man is 3 times old as his son. after 15 years , he will only be twice as old as his son . find their preseny ages​

Answers

Answered by Parvathyvarma
3

Answer:

Step-by-step explanation:

let the present age of the son  be x so the present age of the man = 3x

After 15 years,

age of son  = x+15 and age of man = 3x+15

given,

3x + 15 = 2(x+ 15)

3x + 15 = 2x + 30

3x - 2x = 30 - 15

x = 15 and y = 3x = 3* 15= 45

so the present age of man is 45 years and the present age of son is 15 years

Answered by SarcasticL0ve
4

Given:-

  • A man is 3 times old as his son. after 15 years , he will only be twice as old as his son.

To find:-

  • Present of Man and his son

Solution:-

Let the age of son be x years

Then the age of man will be 3 times as old as his son = 3x

After 15 years

  • Age of son = x + 15

  • Age of man = 3x + 15

According to question,

Man will be only twice as old as his son.

3x + 15 = 2(x + 15)

3x + 15 = 2x + 30

3x = 2x + 15

3x - 2x = 15

x = 15

Therefore,

★ The age of Son (x) = 15 years

★ The age of Man ( 3x ) = 3 × 15 = 45 years

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