A MAN IS 37 YEAR OLD AND HIS TWO SONS ARE 8 AND 3 YEARS OLD. AFTER HOW MANY YEARS WILL HE BE TWICE AS OLD AS THE SUM OF THE AGES OF HIS SONS.
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Given man's age 37 and his elder son's age is 8, So age difference is ED =37–8 = 29 between the man and his elder son. And his younger son's age is 3, age difference is YD= 37–3 = 34 between the man and his younger son. Thus after (42–37 = ) 5 years he becomes twice as old as the sum of the age of his sons.
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After ( 5 years ) he will becomes twice the ages of his sons.
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